Calculate the volume occupied by 18.0 g of water vapor at 100 °C and 1.00 atm.

Question

Quizplus · Accepted Answer

We can use the ideal gas law: PV=nRT, where P=1.00 atm, T=100 °C (convert to Kelvin: 373 K), R=0.0821 L·atm/mol·K, and n=moles of water vapor. We can solve for n by using the molar mass of water (18.0 g/mol) and the given mass of water vapor (18.0 g).

n = (18.0 g) / (18.0 g/mol) = 1.00 mol

Now we can solve for V:

V = (nRT) / P = (1.00 mol)(0.0821 L·atm/mol·K)(373 K) / (1.00 atm) = 30.6 L

Therefore, the volume occupied by 18.0 g of water vapor at 100 °C and 1.00 atm is 30.6 L, which is choice C.

Calculate the Volume Occupied by 18