The density of carbon tetrachloride at 0.94 atm and 398 K is ________.

Question

Quizplus · Accepted Answer

We can use the ideal gas law to solve for density:

PV = nRT

n/V = P/RT

We need to find n/V (molar density) to convert to mass density, which is the same as the density in g/L. We can use the molar mass of carbon tetrachloride to convert from moles to grams:

n/V = (0.94 atm) / [(0.0821 L•atm/mol•K) (398 K)] = 0.0287 mol/L

Density = (0.0287 mol/L) (154 g/mol) = 4.43 g/L

Therefore, the answer is C, 4.43 g/L.

The Density of Carbon Tetrachloride at 0