A coin is tossed times. What is the probability that the coin will land on the toss given that were thrown on the first toss?

Question

A coin is tossed  times. What is the probability that the coin will land  on the  toss given that  were thrown on the first toss?

Quizplus · Accepted Answer

This problem can be solved using conditional probability formula: P(A|B) = P(A intersection B) / P(B). Let A be the event of getting heads on the 11th toss and B be the event of getting heads on the 1st toss. We are given that B has occurred. So, P(B) = 1/2. Now, if B has occurred, then we need to find the probability of A occurring. That means, out of the remaining 10 tosses, we need to get all tails followed by a head. The probability of getting tails is 1/2 and the probability of getting heads is also 1/2. So, the probability of getting all tails followed by a head is (1/2)^11. Hence, P(A intersection B) = (1/2)^11. So, P(A|B) = P(A intersection B) / P(B) = (1/2)^11 / (1/2) = (1/2)^10 = 11eab448_e7e5_e729_acdb_61fdc8b0bad6_TB6027_11. Therefore, the answer is C.

A Coin Is Tossed Times