Predict the major product(s) for the reaction of pent-1-en-4-yne with sodium amide followed by reaction with bromoethane.

Question

Quizplus · Accepted Answer

Sodium amide is a strong base that will deprotonate the terminal alkyne in pent-1-en-4-yne, generating a nucleophile that can then attack bromoethane. This results in the addition of a two-carbon unit to the molecule, extending the chain length from five to seven carbons and maintaining the positions of the double and triple bonds relative to the ends of the molecule, leading to Hept-1-en-4-yne as the product.

Predict the Major Product(s) for the Reaction of Pent-1-En-4-Yne with Sodium