Given that glucose has a specific rotation of +52.8°. Predict the concentration of a glucose aqueous solution contained in a 10 cm long polarimetry tube if a rotation of +15.8° was observed.

Question

Quizplus · Accepted Answer

Firstly, we need to use the formula:

α = (α)C × l

where:
α = observed rotation (+15.8°)
(α)C = specific rotation of glucose (+52.8°)
l = length of polarimetry tube (10 cm)

Rearranging the formula to isolate the concentration (C), we get:

C = α / [(α) l]

C = (+15.8°) / [(+52.8°) × 10 cm]

C = 0.299 g/mL

Therefore, the concentration of the glucose solution is 0.299 g/mL, which is option A.

Given That Glucose Has a Specific Rotation of +52