What is E°_cell for the following reaction,and is it spontaneous or nonspontaneous under standard-state conditions? 2Fe³⁺(aq) + 2H₂O(l) → H₂O₂(aq) + 2H⁺(aq) + 2Fe²⁺(aq)
Given:
H₂O₂(aq) + 2H⁺(aq) + 2e^-
2H₂O(l) E° = 1.77V
Fe³⁺(aq) + e^- Fe²⁺(aq) E° = 0.77V

Question

What is E°_cell for the following reaction,and is it spontaneous or nonspontaneous under standard-state conditions? 2Fe³⁺(aq) + 2H₂O(l) → H₂O₂(aq) + 2H⁺(aq) + 2Fe²⁺(aq)
Given:
H₂O₂(aq) + 2H⁺(aq) + 2e^-

What is E°<sub>cell</sub> for the following reaction,and is it spontaneous or nonspontaneous under standard-state conditions? 2Fe<sup>3+</sup>(aq) + 2H<sub>2</sub>O(l) → H<sub>2</sub>O<sub>2</sub>(aq) + 2H<sup>+</sup>(aq) + 2Fe<sup>2+</sup>(aq) Given: H<sub>2</sub>O<sub>2</sub>(aq) + 2H<sup>+</sup>(aq) + 2e<sup>-</sup> <sup> </sup> 2H<sub>2</sub>O(l) E° = 1.77V Fe<sup>3+</sup>(aq) + e<sup>-</sup> Fe<sup>2+</sup>(aq) E° = 0.77V A) E°<sub>cell</sub> = -1.00 V,nonspontaneous B) E°<sub>cell</sub> = -1.00 V,spontaneous C) E°<sub>cell</sub> = 1.00 V,nonspontaneous D) E°<sub>cell</sub> = 1.00 V,spontaneous E) E°<sub>cell</sub> = -0.23 V,nonspontaneous

2H₂O(l) E° = 1.77V
Fe³⁺(aq) + e^-

Fe²⁺(aq) E° = 0.77V

Quizplus · Accepted Answer

The Answer of What is E°_cell for the following reaction,and is it spontaneous or nonspontaneous under standard-state conditions? 2Fe³⁺(aq)+ 2H₂O(l)→ H₂O₂(aq)+ 2H⁺(aq)+ 2Fe²⁺(aq) Given: H₂O₂(aq)+ 2H⁺(aq)+ 2e^- 2H₂O(l)E° = 1.77V Fe³⁺(aq)+ e^- Fe²⁺(aq)E° = 0.77V

What Is E°cell for the Following Reaction,and Is It Spontaneous

What Is E°_cell for the Following Reaction,and Is It Spontaneous