Predict the products obtained from the electrolysis of a 1 M AlBr₃ solution. Note that 2H₂O(l) + 2e^- → H₂(g) +2OH^-(aq) ,E° = -0.83 V
O₂(g) + 4H⁺(aq) + 4e^- → 2H₂O(l) ,E° = +1.23 V
Br₂(l) + 2e^- → 2Br^-(aq) E° = +1.08 V,and
Al³⁺(aq) + 3e^- → Al(s) E° = -1.66 V

Question

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At the anode, Br- is oxidized to Br2 because it has a less positive potential than water oxidation. At the cathode, water is reduced to H2 because it has a less negative potential than Al3+ reduction.

Predict the Products Obtained from the Electrolysis of a 1