Given Cu2+(aq) + 2e- → Cu(s) E° = +0.34 V Al3+(aq) + 3e- → Al(s) E° = -1.66 V
Na+(aq) + e- → Na(s) E° = -2.71 V
Which of the following reactions will occur?
A) 2Na+(aq) + Cu(s) → Cu2+(aq) + 2Na(s)
B) Al(s) + 3Na+(aq) → Al3+(aq) + 3Na(s)
C) 2Na(s) + Cu2+(aq) → Cu(s) + 2Na+(aq)
D) 2Al3+(aq) + 3Cu(s) → 3Cu2+(aq) + 2Al(s)
E) None of the will occur.
Correct Answer:
Verified
Q67: Which one of the following statements relating
Q70: A voltaic cell consists of a Cd/Cd2+
Q72: What mass of oxygen gas is produced
Q78: What is the minimum voltage required for
Q79: What is the half-reaction that occurs at
Q83: Which is the correct cell diagram for
Q84: Based on the following electrochemical cell,what is
Q91: Which component of the following cell is
Q92: Which of the following elements could be
Q95: Two cells are connected in series, so
Unlock this Answer For Free Now!
View this answer and more for free by performing one of the following actions
Scan the QR code to install the App and get 2 free unlocks
Unlock quizzes for free by uploading documents