If 75.4 J of energy is absorbed by 0.25 mol of CCl₄ at constant pressure,what is the change in temperature? The specific heat of CCl4 is 0.861 J/g·°C.

Question

Quizplus · Accepted Answer

To find the change in temperature, use the formula q = m*c*ΔT. First, calculate the mass of 0.25 mol of CCl4 using its molar mass (153.8 g/mol), which gives 38.45 g. Then, rearrange the formula to solve for ΔT: ΔT = q / (m*c) = 75.4 J / (38.45 g * 0.861 J/g°C) = 2.3°C.

If 754 J of Energy Is Absorbed by 0