Aluminum reacts with bromine to form aluminum bromide (used as an acid catalyst in organic synthesis) . Al(s) + Br₂(l) → Al₂Br₆(s) [unbalanced]
How many moles of Al are needed to form 2.43 mol of Al₂Br₆?

Question

Quizplus · Accepted Answer

From the balanced chemical equation, we see that one mole of Al reacts with one mole of Br2 to form one mole of AlBr3. Therefore, the number of moles of Al needed to form 2.43 mol of AlBr3 is also 2.43 mol. So the answer is 2.43 mol of Al, which corresponds to choice B (since 1 mol of Al forms 1 mol of AlBr3).

Aluminum Reacts with Bromine to Form Aluminum Bromide (Used as an Acid