Z is a standard normal random variable.The P(1.05 $\leq$ z $\leq$ 2.13)equals
A)0.8365
B)0.1303
C)0.4834
D)0.6618

Question

Z is a standard normal random variable.The P(1.05 $\leq$  z $\leq$  2.13)equals​
A)​0.8365
B)​0.1303
C)​0.4834
D)​0.6618

Quizplus · Accepted Answer

Since F1F1F1S1 is a linear combination of Z and F1F1F10 is a constant, F1F1F1S1 is also a standard normal random variable. Therefore, we can use the standard normal distribution table to find the probability: P(1.05 ≤ F1F1F1S1 ≤ 2.13) = Φ(2.13) - Φ(1.05) ≈ 0.1303, where Φ represents the cumulative distribution function of the standard normal distribution.

Z Is a Standard Normal Random Variable ≤\leq≤ Z ≤\leq≤ 213)equals​ A)​0

Z Is a Standard Normal Random Variable $\leq$ Z $\leq$ 213)equals
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