Ti(NH₃)₆³⁺ has a d-orbital electron transition at 399 nm.Find Δ_o at this wavelength.

Question

Quizplus · Accepted Answer

The energy of a photon is given by E = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength. The change in energy (ΔE) for an electron transition is equal to the energy of the photon absorbed or emitted. Therefore, ΔE = hc/λ.In this case, the wavelength of the absorbed photon is 399 nm. Substituting this value into the equation above, we get:ΔE = hc/λ = (6.626 x 10^-34 J s) x (3 x 10^8 m/s) / (399 x 10^-9 m) = 4.99 x 10^-19 JConverting this to kJ/mol, we get:ΔE = (4.99 x 10^-19 J) x (1 kJ / 1000 J) x (6.022 x 10^23 mol^-1) = 300 kJ/molTherefore, the correct answer is A.

Ti(NH3)63+ Has a D-Orbital Electron Transition at 399 Nm

Ti(NH₃)₆³⁺ Has a D-Orbital Electron Transition at 399 Nm