If 25.00 mL of 0.200 M HCl is titrated with 0.200 M NaOH,what is the pH of the solution after the addition of 22.50 mL of NaOH?

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Initially, there are 5.00 mmol of HCl. After adding 22.50 mL of 0.200 M NaOH, 4.50 mmol of NaOH are added. This leaves 0.50 mmol of HCl unreacted in a total volume of 47.50 mL. The concentration of HCl is 0.50 mmol / 47.50 mL = 0.0105 M. The pH is -log(0.0105) = 1.98.

If 2500 ML of 0