Sodium carbonate,Na₂CO₃,can be titrated with HCl according to the following balanced chemical equation. 2H⁺(aq) + CO₃²⁻(aq) → H₂O(l) + CO₂(g)
What volume of 0.2000 M HCl is necessary to titrate 0.3462 g of sodium carbonate?

Question

Quizplus · Accepted Answer

The balanced chemical equation shows that 2 moles of HCl react with 1 mole of Na2CO3. First, calculate the moles of Na2CO3: its molar mass is approximately 106 g/mol, so 0.3462 g corresponds to 0.3462 g / 106 g/mol = 0.003267 moles. Since the stoichiometry of the reaction requires twice as many moles of HCl, you need 0.003267 moles * 2 = 0.006534 moles of HCl. Given that the concentration of HCl is 0.2000 M, the volume of HCl needed is 0.006534 moles / 0.2000 M = 0.03267 L, or 32.67 mL.

Sodium Carbonate,Na2CO3,can Be Titrated with HCl According to the Following

Sodium Carbonate,Na₂CO₃,can Be Titrated with HCl According to the Following