If 77.5 g of ethylene glycol (HOCH₂CH₂OH)is added to 422.5 g of water,what is the mole fraction of ethylene glycol?

Question

Quizplus · Accepted Answer

To find the mole fraction of ethylene glycol, we need to first find the moles of ethylene glycol and water.

Moles of ethylene glycol = mass / molar mass = 77.5 g / 62.07 g/mol = 1.25 mol
Moles of water = mass / molar mass = 422.5 g / 18.015 g/mol = 23.45 mol

Total moles = 1.25 mol + 23.45 mol = 24.7 mol

Mole fraction of ethylene glycol = moles of ethylene glycol / total moles
= 1.25 mol / 24.7 mol
= 0.0506

Therefore, the mole fraction of ethylene glycol is 0.0506 or choice B.

If 775 G of Ethylene Glycol (HOCH2CH2OH)is Added to 422

If 775 G of Ethylene Glycol (HOCH₂CH₂OH)is Added to 422