At 1.00 atm,1.64 × 10−³ g H₂(g)will dissolve in 1.0 L of water.What pressure of gas is necessary to obtain a concentration of 1.0 × 10−³ M H₂(g)?

Question

Quizplus · Accepted Answer

The solubility of a gas in a liquid is directly proportional to the pressure of the gas above the liquid (Henry's Law). Since the concentration of $HSO_3^-$ at 1 atm is $1.64 \times 10^{-3} M$ and we want to increase it to $1.0 \times 10^{-3} M$, we can use the proportionality to find the required pressure. Given that the concentration increases by approximately 0.61 times (from $1.64 \times 10^{-3} M$ to $1.0 \times 10^{-3} M$), the pressure needed to achieve this higher concentration is $1.00 \, \text{atm} / 0.61 \approx 1.2 \, \text{atm}$.

At 100 Atm,1