The molal boiling point constant for water is 0.52°C/m.At what temperature will a mixture of 45.0 g of NaCl and 0.500 kg of water boil?

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Quizplus · Accepted Answer

The boiling point elevation can be calculated using the formula ΔT = i * K_b * m, where i is the van't Hoff factor (2 for NaCl), K_b is the boiling point elevation constant (0.52°C/m), and m is the molality. First, calculate the molality: moles of NaCl = 45.0 g / 58.44 g/mol = 0.770 moles; molality = 0.770 moles / 0.500 kg = 1.54 m. Then, ΔT = 2 * 0.52°C/m * 1.54 m = 1.60°C. The new boiling point is 100.0°C + 1.60°C = 101.6°C.

The Molal Boiling Point Constant for Water Is 0