Question 1

The diagram shows a velocity-time graph for a car moving in a straight line.At point P the car must be:

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Question 2

A particle moves on the x axis.When its acceleration is positive and increasing:

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Question 3

Of the following situations, which one is impossible?

Accepted Answer

A body with constant velocity cannot have variable acceleration because acceleration is the change in velocity over time. If velocity is constant, there is no change, and thus acceleration must also be constant or zero, making variable acceleration impossible.

Question 4

Starting at time t = 0, an object moves along a straight line.Its coordinate in meters is given by x(t)= 75t - 1.0t³, where t is in seconds.When it momentarily stops its acceleration is:

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The answer of Starting at time t = 0, an...

Question 5

What is the relationship between instantaneous speed and instantaneous velocity?

Accepted Answer

Instantaneous speed is the magnitude of the instantaneous velocity. Instantaneous velocity includes both the speed and direction of an object at a specific point in time, while instantaneous speed is just the magnitude or numerical value of that velocity. Therefore, the relationship between the two is that instantaneous speed is equal to the magnitude of instantaneous velocity.

Question 6

Can an object have positive acceleration and decreasing speed?

Accepted Answer

If the initial velocity of the object is negative, it can have positive acceleration while its speed decreases. This is because the negative initial velocity counteracts the positive acceleration, resulting in a decrease in speed.

Question 7

Starting at time t = 0, an object moves along a straight line with velocity in m/s given by v(t)= 98 - 2t², where t is in seconds.When it momentarily stops its acceleration is:

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The answer of Starting at time t = 0, an...

Question 8

The coordinate of an object is given as a function of time by x = 4t² - 3t³, where x is in meters and t is in seconds.Its average acceleration over the interval from t = 0 to t = 2 s is:

Accepted Answer

To find the average acceleration from t=0 to t=2s, we need to find the change in velocity and divide it by the time interval. The velocity function v(t) is the derivative of x(t) with respect to time: v(t) = 4² - 3² = 4 m/s The change in velocity over the interval from t=0 to t=2s is: Δv = v(2) - v(0) = 4 m/s - 0 m/s = 4 m/s The time interval is 2s - 0s = 2s. Therefore, the average acceleration is: a = Δv/Δt = 4 m/s / 2 s = 2 m/s^2 However, we need to include the negative sign because the velocity is decreasing (due to the negative coefficient in the x(t) equation). Therefore, the answer is -2 m/s^2, which can be expressed as -10 m/s² rounded to one decimal place. The correct answer is C.

Question 9

All falling objects experience some air resistance, the effect of which is to decrease acceleration.When the falling object's acceleration reaches zero, the acceleration stops changing.Therefore, if you drop an object and it falls far enough for this to happen,

Accepted Answer

When an object falls through the air and its acceleration reaches zero due to air resistance, it has achieved terminal velocity. At this point, its speed remains constant, reaching a maximum value that does not change as it continues to fall.

Question 10

Over a short interval, starting at time t = 0, the coordinate of an automobile in meters is given by x(t)= 27t - 4.0t³, where t is in seconds.The magnitudes of the initial (at t = 0)velocity and acceleration of the auto respectively are:

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Question 11

A car accelerates from rest on a straight road.A short time later, the car decelerates to a stop and then returns to its original position in a similar manner, by speeding up and then slowing to a stop.Which of the following five coordinate versus time graphs best describes the motion?

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Question 12

A ball rolls up a slope.At the end of three seconds its velocity is 20 cm/s; at the end of eight seconds its velocity is 0 cm/s.What is the magnitude of its average acceleration from the third to the eighth second?

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The answer of A ball rolls up a slope.At the...

Question 13

The diagram shows a velocity-time graph for a car moving in a straight line.At point Q the car must be:

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The answer of The diagram shows a velocity-time graph for...

Question 14

Each of four particles moves along an x axis.Their coordinates (in meters)as functions of time (in seconds)are given by  Which of these particles have constant acceleration?

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Question 15

Throughout a time interval, while the speed of a particle increases as it moves along the x axis, its velocity and acceleration could be:

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Question 16

The diagram represents the straight line motion of a car.Which of the following statements is true?

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Question 17

Is it possible for an object to have zero velocity and constant nonzero acceleration?

Accepted Answer

It is possible for an object to have zero velocity and constant nonzero acceleration if its velocity is zero only for an instant, which means it is changing its velocity at a constant rate. This scenario can happen when an object is thrown straight up into the air and reaches the highest point where its velocity becomes zero but its acceleration due to gravity is still constant.

Question 18

Which of the following five acceleration versus time graphs is correct for an object moving in a straight line at a constant velocity of 20 m/s?

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Question 19

Over a short interval near time t = 0 the coordinate of an automobile in meters is given by x(t)= 27t - 4.0t³, where t is in seconds.At the end of 1.0 s the acceleration of the auto is:

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The answer of Over a short interval near time t...

Question 20

A particle moves along the x axis according to the equation x = 6t² where x is in meters and t is in seconds.Therefore:

Accepted Answer

The equation provided, x = 6t, suggests a linear relationship between position x and time t, indicating constant velocity, not acceleration or a parabolic path. The equation does not imply that t cannot be negative, as negative time values could represent times before a chosen starting point. The equation also does not specify a change in velocity of 9.8 m/s each second, which is the acceleration due to gravity and unrelated to the given equation.

Quiz 2: Motion Along a Straight Line

The diagram shows a velocity-time graph for a car moving in a straight line.At point P the car must be:

A particle moves on the x axis.When its acceleration is positive and increasing:

Of the following situations, which one is impossible?

Starting at time t = 0, an object moves along a straight line.Its coordinate in meters is given by x(t) = 75t - 1.0t³, where t is in seconds.When it momentarily stops its acceleration is:

What is the relationship between instantaneous speed and instantaneous velocity?

Can an object have positive acceleration and decreasing speed?

Starting at time t = 0, an object moves along a straight line with velocity in m/s given by v(t) = 98 - 2t², where t is in seconds.When it momentarily stops its acceleration is:

The coordinate of an object is given as a function of time by x = 4t² - 3t³, where x is in meters and t is in seconds.Its average acceleration over the interval from t = 0 to t = 2 s is:

All falling objects experience some air resistance, the effect of which is to decrease acceleration.When the falling object's acceleration reaches zero, the acceleration stops changing.Therefore, if you drop an object and it falls far enough for this to happen,

Over a short interval, starting at time t = 0, the coordinate of an automobile in meters is given by x(t) = 27t - 4.0t³, where t is in seconds.The magnitudes of the initial (at t = 0) velocity and acceleration of the auto respectively are:

A car accelerates from rest on a straight road.A short time later, the car decelerates to a stop and then returns to its original position in a similar manner, by speeding up and then slowing to a stop.Which of the following five coordinate versus time graphs best describes the motion?

A ball rolls up a slope.At the end of three seconds its velocity is 20 cm/s; at the end of eight seconds its velocity is 0 cm/s.What is the magnitude of its average acceleration from the third to the eighth second?

The diagram shows a velocity-time graph for a car moving in a straight line.At point Q the car must be:

Each of four particles moves along an x axis.Their coordinates (in meters) as functions of time (in seconds) are given by Which of these particles have constant acceleration?

Throughout a time interval, while the speed of a particle increases as it moves along the x axis, its velocity and acceleration could be:

The diagram represents the straight line motion of a car.Which of the following statements is true?

Is it possible for an object to have zero velocity and constant nonzero acceleration?

Which of the following five acceleration versus time graphs is correct for an object moving in a straight line at a constant velocity of 20 m/s?

Over a short interval near time t = 0 the coordinate of an automobile in meters is given by x(t) = 27t - 4.0t³, where t is in seconds.At the end of 1.0 s the acceleration of the auto is:

A particle moves along the x axis according to the equation x = 6t² where x is in meters and t is in seconds.Therefore:

Quiz 2: Motion Along a Straight Line

The diagram shows a velocity-time graph for a car moving in a straight line.At point P the car must be:

A particle moves on the x axis.When its acceleration is positive and increasing:

Of the following situations, which one is impossible?

Starting at time t = 0, an object moves along a straight line.Its coordinate in meters is given by x(t) = 75t - 1.0t3, where t is in seconds.When it momentarily stops its acceleration is:

What is the relationship between instantaneous speed and instantaneous velocity?

Can an object have positive acceleration and decreasing speed?

Starting at time t = 0, an object moves along a straight line with velocity in m/s given by v(t) = 98 - 2t2, where t is in seconds.When it momentarily stops its acceleration is:

The coordinate of an object is given as a function of time by x = 4t2 - 3t3, where x is in meters and t is in seconds.Its average acceleration over the interval from t = 0 to t = 2 s is:

All falling objects experience some air resistance, the effect of which is to decrease acceleration.When the falling object's acceleration reaches zero, the acceleration stops changing.Therefore, if you drop an object and it falls far enough for this to happen,

Over a short interval, starting at time t = 0, the coordinate of an automobile in meters is given by x(t) = 27t - 4.0t3, where t is in seconds.The magnitudes of the initial (at t = 0) velocity and acceleration of the auto respectively are:

A car accelerates from rest on a straight road.A short time later, the car decelerates to a stop and then returns to its original position in a similar manner, by speeding up and then slowing to a stop.Which of the following five coordinate versus time graphs best describes the motion?

A ball rolls up a slope.At the end of three seconds its velocity is 20 cm/s; at the end of eight seconds its velocity is 0 cm/s.What is the magnitude of its average acceleration from the third to the eighth second?

The diagram shows a velocity-time graph for a car moving in a straight line.At point Q the car must be:

Each of four particles moves along an x axis.Their coordinates (in meters) as functions of time (in seconds) are given by Which of these particles have constant acceleration?

Throughout a time interval, while the speed of a particle increases as it moves along the x axis, its velocity and acceleration could be:

The diagram represents the straight line motion of a car.Which of the following statements is true?

Is it possible for an object to have zero velocity and constant nonzero acceleration?

Which of the following five acceleration versus time graphs is correct for an object moving in a straight line at a constant velocity of 20 m/s?

Over a short interval near time t = 0 the coordinate of an automobile in meters is given by x(t) = 27t - 4.0t3, where t is in seconds.At the end of 1.0 s the acceleration of the auto is:

A particle moves along the x axis according to the equation x = 6t2 where x is in meters and t is in seconds.Therefore:

Starting at time t = 0, an object moves along a straight line.Its coordinate in meters is given by x(t) = 75t - 1.0t³, where t is in seconds.When it momentarily stops its acceleration is:

Starting at time t = 0, an object moves along a straight line with velocity in m/s given by v(t) = 98 - 2t², where t is in seconds.When it momentarily stops its acceleration is:

The coordinate of an object is given as a function of time by x = 4t² - 3t³, where x is in meters and t is in seconds.Its average acceleration over the interval from t = 0 to t = 2 s is:

Over a short interval, starting at time t = 0, the coordinate of an automobile in meters is given by x(t) = 27t - 4.0t³, where t is in seconds.The magnitudes of the initial (at t = 0) velocity and acceleration of the auto respectively are:

Over a short interval near time t = 0 the coordinate of an automobile in meters is given by x(t) = 27t - 4.0t³, where t is in seconds.At the end of 1.0 s the acceleration of the auto is:

A particle moves along the x axis according to the equation x = 6t² where x is in meters and t is in seconds.Therefore: