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Mathematics
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Finite Mathematics and Applied Calculus
Quiz 9: Random Variables and Statistics
Path 4
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Question 81
Short Answer
Find the expected value of a random variable X having the following probability distribution:
x
2
4
6
8
P
(
X
=
x
)
7
20
2
20
5
20
6
20
\begin{array} { c c c c c } x & 2 & 4 & 6 & 8 \\P ( X = x ) & \frac { 7 } { 20 } & \frac { 2 } { 20 } & \frac { 5 } { 20 } & \frac { 6 } { 20 }\end{array}
x
P
(
X
=
x
)
2
20
7
4
20
2
6
20
5
8
20
6
E
(
X
)
=
E ( X ) =
E
(
X
)
=
__________
Question 82
Short Answer
Calculate the expected value of X for the given probability distribution.
x
0
1
2
3
P
(
X
=
x
)
0.4
0.2
0.2
0.2
\begin{array} { c c c c c } x & 0 & 1 & 2 & 3 \\P ( X = x ) & 0.4 & 0.2 & 0.2 & 0.2\end{array}
x
P
(
X
=
x
)
0
0.4
1
0.2
2
0.2
3
0.2
E
(
X
)
=
E ( X ) =
E
(
X
)
=
__________
Question 83
Multiple Choice
Calculate the expected value of X for the given probability distribution:
x
−
5
−
1
0
2
5
10
P
(
X
=
x
)
0.1
0.1
0.1
0.1
0.1
0.5
\begin{array} { c c c c c c c } x & - 5 & - 1 & 0 & 2 & 5 & 10 \\P ( X = x ) & 0.1 & 0.1 & 0.1 & 0.1 & 0.1 & 0.5\end{array}
x
P
(
X
=
x
)
−
5
0.1
−
1
0.1
0
0.1
2
0.1
5
0.1
10
0.5
Round your answer to two decimal places if necessary.
Question 84
Multiple Choice
Select five cards without replacement from a standard deck of 52, and let X be the number of black cards you draw. Calculate the expected value of the given random variable X.
Question 85
Multiple Choice
The following table shows the approximate numbers of school goers in the U.S. (residents who attended some educational institution) in 1998, broken down by age group. Use the rounded midpoints of the given measurement classes to compute the probability distribution of the age X of a school goer. (Round probabilities to two decimal places.) Hence compute the expected value of X.
Age
3
−
6.9
7
−
12.9
13
−
16.9
17
−
22.9
23
−
26.9
27
−
42.9
Population
(Millions)
11
22
16
15
4
7
\begin{array} { c c c c c c c } \text { Age } & 3 - 6.9 & 7 - 12.9 & 13 - 16.9 & 17 - 22.9 & 23 - 26.9 & 27 - 42.9 \\\begin{array} { c } \text { Population } \\\text { (Millions) }\end{array} & 11 & 22 & 16 & 15 & 4 & 7\end{array}
Age
Population
(Millions)
3
−
6.9
11
7
−
12.9
22
13
−
16.9
16
17
−
22.9
15
23
−
26.9
4
27
−
42.9
7
Question 86
Short Answer
Calculate the expected value of X for the given probability distribution.
x
1
2
3
4
P
(
X
=
x
)
0.4
0.2
0.2
0.2
\begin{array} { c c c c c } x & 1 & 2 & 3 & 4 \\P ( X = x ) & 0.4 & 0.2 & 0.2 & 0.2\end{array}
x
P
(
X
=
x
)
1
0.4
2
0.2
3
0.2
4
0.2
E
(
X
)
=
E ( X ) =
E
(
X
)
=
__________
Question 87
Short Answer
Find the expected value of a random variable X having the following probability distribution:
x
10
20
30
40
P
(
X
=
x
)
25
60
20
60
5
60
10
60
\begin{array} { c c c c c } x & 10 & 20 & 30 & 40 \\P ( X = x ) & \frac { 25 } { 60 } & \frac { 20 } { 60 } & \frac { 5 } { 60 } & \frac { 10 } { 60 }\end{array}
x
P
(
X
=
x
)
10
60
25
20
60
20
30
60
5
40
60
10
E
(
X
)
=
E ( X ) =
E
(
X
)
=
__________
Question 88
Short Answer
Given the probability distribution below, calculate the expected value of X.
x
−
4
−
2
0
3
7
16
P
(
X
=
x
)
0.1
0.2
0.3
0.2
0
0.2
\begin{array} { c c c c c c c } x & - 4 & - 2 & 0 & 3 & 7 & 16 \\P ( X = x ) & 0.1 & 0.2 & 0.3 & 0.2 & 0 & 0.2\end{array}
x
P
(
X
=
x
)
−
4
0.1
−
2
0.2
0
0.3
3
0.2
7
0
16
0.2
μ
=
E
(
X
)
\mu = E ( X )
μ
=
E
(
X
)
__________
Question 89
Multiple Choice
The following is a sample of tow ratings (in pounds) for some popular 2000 model sport utility vehicles. 6,400, 12,800, 19,200, 25,600, 32,000, 38,400 Compute the median.
Question 90
Multiple Choice
Given the data.
2.4
,
−
5.2
,
4.7
,
−
0.5
,
−
0.5
2.4 , - 5.2,4.7 , - 0.5 , - 0.5
2.4
,
−
5.2
,
4.7
,
−
0.5
,
−
0.5
Compute the median.
Question 91
Multiple Choice
The following figures show the price of silver in dollars per ounce for the 10-business day period April 4 - April 15, 2004. 7) 0, 6.7, 7.0, 7.3, 7.0, 7.4, 7.4, 7.4, 7.3, 7.3 Find the sample median.