Question 1

When 5.0 C of charge moves at constant speed along a path between two points differing in potential by 12 V, the amount of work done by the field is

Accepted Answer

The work done by the electric field is calculated using the formula W = QV, where Q is the charge and V is the potential difference. Here, W = 5.0 C * 12 V = 60 J.

Question 2

Two parallel metal plates 0.35 cm apart have a potential difference between them of 175 V. The electric force on a positive charge of 6.4 × 10^-19 C at a point midway between the plates is approximately

Accepted Answer

The answer of Two parallel metal plates 0.35 cm apart...

Question 3

Two parallel horizontal plates are spaced 0.40 cm apart in air. You introduce an oil droplet of mass 4.9 × 10^-17 kg between the plates. If the droplet carries two electronic charges and if there were no air buoyancy, you could hold the droplet motionless between the plates if you kept the potential difference between them at

Accepted Answer

The electric force must balance the gravitational force. Using F = qE and E = V/d, where q is the charge (2e), V is the potential difference, and d is the distance between plates, we find V = mgd/q. Substituting the given values, V = 6.0 V.

Question 4

Charges +Q and -Q are arranged at the corners of a square as shown. When the electric field E and the electric potential V are determined at P, the center of the square, we find that

Accepted Answer

The answer of  Charges +Q and -Q are arranged...

Question 5

When 2.0 C of charge moves at constant speed along a path between two points differing in potential by 6.0 V, the amount of work done by the field is

Accepted Answer

The answer of When 2.0 C of charge moves at...

Question 6

A uniform electric field exists between two parallel plates separated by 1.2 cm. The intensity of the field is 23 kN/C. What is the potential difference between the plates?

Accepted Answer

The answer of A uniform electric field exists between two...

Question 7

The electrical potential 2.5 cm from a point charge of Q₁= +4.5 × 10^-9 C and 2.0 cm from a second charge Q₂ is 3.2 kV. Find Q₂.

Accepted Answer

The answer of The electrical potential 2.5 cm from a...

Question 8

A uniform electric field exists between two parallel plates separated by 2.0 cm. The intensity of the field is 15 kN/C. What is the potential difference between the plates?

Accepted Answer

The answer of A uniform electric field exists between two...

Question 9

The electrostatic potential as a function of distance along a certain line in space is shown in graph 1). Which of the curves in graph 2) is most likely to represent the electric field as a function of distance along the same line?

Accepted Answer

The answer of  The electrostatic potential as a function...

Question 10

Two parallel horizontal plates are spaced 0.60 cm apart in air. You introduce an oil droplet of mass 7.4 × 10^-17 kg between the plates. If the droplet carries 5 electronic charges and if there were no air buoyancy, you could hold the droplet motionless between the plates if you kept the potential difference between them at

Accepted Answer

The electric force on the droplet is equal to the gravitational force on the droplet. The electric force is given by F = qE, where q is the charge on the droplet and E is the electric field between the plates. The gravitational force is given by F = mg, where m is the mass of the droplet and g is the acceleration due to gravity. Setting these two forces equal to each other, we get qE = mg. Solving for E, we get E = mg/q. Substituting the given values, we get E = (7.4 × 10^-17 kg)(9.8 m/s^2)/(5e) = 1.48 × 10^4 V/m. The potential difference between the plates is given by V = Ed, where d is the distance between the plates. Substituting the given values, we get V = (1.48 × 10^4 V/m)(0.60 cm) = 5.4 V.

Question 11

The magnitude of the electric field in a region is given by E = kQ / r² where Q is the charge. What is the potential difference between r = a to r = b?

Accepted Answer

The answer of The magnitude of the electric field in...

Question 12

Two parallel metal plates 5.0 cm apart have a potential difference between them of 75 V. The electric force on a positive charge of 3.2 × 10^-19 C at a point midway between the plates is approximately

Accepted Answer

The answer of Two parallel metal plates 5.0 cm apart...

Question 13

Electric field in a region is created by a point charge Q located at r = 0. What is the potential difference as one moves from a closer point r = a to a farther location r = b?

Accepted Answer

The answer of Electric field in a region is created...

Question 14

A lithium nucleus with a charge of 31.6 × 10^-19) C and a mass of 71.67 × 10^-27) kg, and an alpha particle with a charge of 21.6 × 10^-19) C and a mass of 41.67 × 10^-27) kg, are at rest. They could be accelerated to the same kinetic energy by

Accepted Answer

The answer of A lithium nucleus with a charge of...

Question 15

An electric dipole that has a positive charge of 4.8 × 10^-19 C is separated from a negative charge of the same magnitude by 6.4 × 10^-10 m. The electric potential at a point 9.2 × 10^-10 m from each of the two charges is

Accepted Answer

The electric potential at a point equidistant from both charges of a dipole is zero because the contributions from the positive and negative charges cancel each other out.

Question 16

Correct units for electric potential are

Accepted Answer

Electric potential is measured in volts, which is equivalent to joules per coulomb (J/C). This unit represents the work done per unit charge.

Question 17

The concept of difference in electric potential is most closely associated with

Accepted Answer

Difference in electric potential is defined as the amount of work done per unit quantity of electricity (or charge) in moving a positive test charge from one point to another in an electric field. It is commonly referred to as voltage and is measured in volts (V). Therefore, the best answer is E.

Question 18

Charges Q and q Q ≠ q), separated by a distance d, produce a potential V_P = 0 at point P. This means that

Accepted Answer

The answer of  Charges Q and q Q ≠...

Question 19

The potential at a point due to a unit positive charge is found to be V. If the distance between the charge and the point is tripled, the potential becomes

Accepted Answer

According to the problem, the equipotential lines are at 100 V interval, which means the potential difference between two adjacent lines is 100 V. This also means that the potential difference between any two points on the same equipotential line is 100 V.

Now, let's consider the potential at a point due to a unit positive charge to be V. If we triple the distance between the charge and the point, the distance becomes 3x. We know that the potential due to a point charge varies inversely with the distance, so the new potential would be V/3.

Therefore, the potential becomes V/3 when the distance between the charge and the point is tripled. This matches with option A, so it is the correct choice.

Question 20

The electron volt is a unit of

Accepted Answer

The electron volt (eV) is a unit of energy that is commonly used in physics and electrical engineering. It is the amount of energy that an electron gains (or loses) as it moves through a potential difference of one volt.

Quiz 17: Electrostatics II: Electric Potential Energy and Electric Potential

When 5.0 C of charge moves at constant speed along a path between two points differing in potential by 12 V, the amount of work done by the field is

Two parallel metal plates 0.35 cm apart have a potential difference between them of 175 V. The electric force on a positive charge of 6.4 × 10^-19 C at a point midway between the plates is approximately

Charges +Q and -Q are arranged at the corners of a square as shown. When the electric field E and the electric potential V are determined at P, the center of the square, we find that

When 2.0 C of charge moves at constant speed along a path between two points differing in potential by 6.0 V, the amount of work done by the field is

A uniform electric field exists between two parallel plates separated by 1.2 cm. The intensity of the field is 23 kN/C. What is the potential difference between the plates?

The electrical potential 2.5 cm from a point charge of Q₁= +4.5 × 10^-9 C and 2.0 cm from a second charge Q₂ is 3.2 kV. Find Q₂.

A uniform electric field exists between two parallel plates separated by 2.0 cm. The intensity of the field is 15 kN/C. What is the potential difference between the plates?

The electrostatic potential as a function of distance along a certain line in space is shown in graph 1) . Which of the curves in graph 2) is most likely to represent the electric field as a function of distance along the same line?

The magnitude of the electric field in a region is given by E = kQ / r² where Q is the charge. What is the potential difference between r = a to r = b?

Two parallel metal plates 5.0 cm apart have a potential difference between them of 75 V. The electric force on a positive charge of 3.2 × 10^-19 C at a point midway between the plates is approximately

Electric field in a region is created by a point charge Q located at r = 0. What is the potential difference as one moves from a closer point r = a to a farther location r = b?

A lithium nucleus with a charge of 31.6 × 10^-19) C and a mass of 71.67 × 10^-27) kg, and an alpha particle with a charge of 21.6 × 10^-19) C and a mass of 41.67 × 10^-27) kg, are at rest. They could be accelerated to the same kinetic energy by

An electric dipole that has a positive charge of 4.8 × 10^-19 C is separated from a negative charge of the same magnitude by 6.4 × 10^-10 m. The electric potential at a point 9.2 × 10^-10 m from each of the two charges is

Correct units for electric potential are

The concept of difference in electric potential is most closely associated with

Charges Q and q Q ≠ q) , separated by a distance d, produce a potential V_P = 0 at point P. This means that

The potential at a point due to a unit positive charge is found to be V. If the distance between the charge and the point is tripled, the potential becomes

The electron volt is a unit of

Quiz 17: Electrostatics II: Electric Potential Energy and Electric Potential

When 5.0 C of charge moves at constant speed along a path between two points differing in potential by 12 V, the amount of work done by the field is

Two parallel metal plates 0.35 cm apart have a potential difference between them of 175 V. The electric force on a positive charge of 6.4 × 10-19 C at a point midway between the plates is approximately

Charges +Q and -Q are arranged at the corners of a square as shown. When the electric field E and the electric potential V are determined at P, the center of the square, we find that

When 2.0 C of charge moves at constant speed along a path between two points differing in potential by 6.0 V, the amount of work done by the field is

A uniform electric field exists between two parallel plates separated by 1.2 cm. The intensity of the field is 23 kN/C. What is the potential difference between the plates?

The electrical potential 2.5 cm from a point charge of Q1 = +4.5 × 10-9 C and 2.0 cm from a second charge Q2 is 3.2 kV. Find Q2.

A uniform electric field exists between two parallel plates separated by 2.0 cm. The intensity of the field is 15 kN/C. What is the potential difference between the plates?

The electrostatic potential as a function of distance along a certain line in space is shown in graph 1) . Which of the curves in graph 2) is most likely to represent the electric field as a function of distance along the same line?

The magnitude of the electric field in a region is given by E = kQ / r2 where Q is the charge. What is the potential difference between r = a to r = b?

Two parallel metal plates 5.0 cm apart have a potential difference between them of 75 V. The electric force on a positive charge of 3.2 × 10-19 C at a point midway between the plates is approximately

Electric field in a region is created by a point charge Q located at r = 0. What is the potential difference as one moves from a closer point r = a to a farther location r = b?

A lithium nucleus with a charge of 31.6 × 10-19) C and a mass of 71.67 × 10-27) kg, and an alpha particle with a charge of 21.6 × 10-19) C and a mass of 41.67 × 10-27) kg, are at rest. They could be accelerated to the same kinetic energy by

An electric dipole that has a positive charge of 4.8 × 10-19 C is separated from a negative charge of the same magnitude by 6.4 × 10-10 m. The electric potential at a point 9.2 × 10-10 m from each of the two charges is

Correct units for electric potential are

The concept of difference in electric potential is most closely associated with

Charges Q and q Q ≠ q) , separated by a distance d, produce a potential VP = 0 at point P. This means that

The potential at a point due to a unit positive charge is found to be V. If the distance between the charge and the point is tripled, the potential becomes

The electron volt is a unit of

Two parallel metal plates 0.35 cm apart have a potential difference between them of 175 V. The electric force on a positive charge of 6.4 × 10^-19 C at a point midway between the plates is approximately

The electrical potential 2.5 cm from a point charge of Q₁= +4.5 × 10^-9 C and 2.0 cm from a second charge Q₂ is 3.2 kV. Find Q₂.

The magnitude of the electric field in a region is given by E = kQ / r² where Q is the charge. What is the potential difference between r = a to r = b?

Two parallel metal plates 5.0 cm apart have a potential difference between them of 75 V. The electric force on a positive charge of 3.2 × 10^-19 C at a point midway between the plates is approximately

A lithium nucleus with a charge of 31.6 × 10^-19) C and a mass of 71.67 × 10^-27) kg, and an alpha particle with a charge of 21.6 × 10^-19) C and a mass of 41.67 × 10^-27) kg, are at rest. They could be accelerated to the same kinetic energy by

An electric dipole that has a positive charge of 4.8 × 10^-19 C is separated from a negative charge of the same magnitude by 6.4 × 10^-10 m. The electric potential at a point 9.2 × 10^-10 m from each of the two charges is

Charges Q and q Q ≠ q) , separated by a distance d, produce a potential V_P = 0 at point P. This means that