Use truth tables to test the validity of the argument.
-$\begin{array} { l }
\sim \mathrm { q } { \wedge } \sim \mathrm { p } \
\mathrm { p } \vee \sim \mathrm { q }\
\hline \therefore \sim \mathrm { q }
\end{array}$

A) Valid
B) Invalid

Question

Use truth tables to test the validity of the argument.
-$\begin{array} { l } 
\sim \mathrm { q }  { \wedge } \sim \mathrm { p } \
 \mathrm { p } \vee \sim \mathrm { q }\
\hline \therefore \sim \mathrm { q } 
\end{array}$

A) Valid
B) Invalid

Quizplus · Accepted Answer

The argument is valid because, in every case where the premises are true, the conclusion is also true. The first premise $\sim q \wedge \sim p$ implies that $q$ is false. The second premise $p \vee \sim q$ is always true because $\sim q$ is true (from the first premise). Therefore, the conclusion $\sim q$ (not $q$) is always true whenever the premises are true, making the argument valid.

Use Truth Tables to Test the Validity of the Argument