Use truth tables to test the validity of the argument.
-$\begin{array} { l }
\mathrm { p } \wedge \sim \mathrm { q } \
\mathrm { p } \vee \mathrm { q } \
\hline \therefore \mathrm { p }
\end{array}$

A) Valid
B) Invalid

Question

Use truth tables to test the validity of the argument.
-$\begin{array} { l } 
\mathrm { p } \wedge \sim \mathrm { q } \
 \mathrm { p } \vee \mathrm { q } \
\hline  \therefore \mathrm { p } 
\end{array}$

A) Valid
B) Invalid

Quizplus · Accepted Answer

The argument is valid because in every scenario where both premises are true, the conclusion $p$ is also true. The first premise $p \wedge \sim q$ requires $p$ to be true and $q$ to be false. The second premise $p \vee q$ is satisfied under any condition where either $p$ or $q$ (or both) is true. Since the first premise necessitates $p$ being true, the conclusion $p$ is always true whenever the premises are, making the argument valid.

Use Truth Tables to Test the Validity of the Argument p∧∼qp∨q∴p\begin{array} { l } \mathrm { p } \wedge \sim \mathrm { q } \\ \mathrm { p } \vee \mathrm { q } \\\hline \therefore \mathrm { p } \end{array}p∧∼qp∨q∴p​​

Use Truth Tables to Test the Validity of the Argument $\begin{array} { l } \mathrm { p } \wedge \sim \mathrm { q } \\ \mathrm { p } \vee \mathrm { q } \\\hline \therefore \mathrm { p } \end{array}$