Use truth tables to test the validity of the argument.
-$\begin{array} { l }
\mathrm { p } \vee \mathrm { q } \
\sim ( \mathrm { p } \vee \mathrm { q } ) \
\hline\therefore \sim \mathrm { q }
\end{array}$

A) Valid
B) Invalid

Question

Use truth tables to test the validity of the argument.
-$\begin{array} { l } 
\mathrm { p } \vee \mathrm { q } \
\sim ( \mathrm { p } \vee \mathrm { q } ) \
\hline\therefore \sim \mathrm { q }
\end{array}$

A) Valid
B) Invalid

Quizplus · Accepted Answer

The argument is valid because the premises contradict each other, so the conclusion must be true.

Use Truth Tables to Test the Validity of the Argument p∨q∼(p∨q)∴∼q\begin{array} { l } \mathrm { p } \vee \mathrm { q } \\\sim ( \mathrm { p } \vee \mathrm { q } ) \\\hline\therefore \sim \mathrm { q }\end{array}p∨q∼(p∨q)∴∼q​​

Use Truth Tables to Test the Validity of the Argument $\begin{array} { l } \mathrm { p } \vee \mathrm { q } \\\sim ( \mathrm { p } \vee \mathrm { q } ) \\\hline\therefore \sim \mathrm { q }\end{array}$