Identify the standard form of the argument.
-$\begin{array} { l }
\mathrm { p } \rightarrow \mathrm { q } \
\sim \mathrm { p } \
\hline\therefore \sim \mathrm { q }
\end{array}$

A) Law of Syllogism
B) Law of Contraposition
C) Fallacy of the Converse
D) Fallacy of the Inverse

Question

Identify the standard form of the argument.
-$\begin{array} { l } 
\mathrm { p } \rightarrow \mathrm { q } \
\sim \mathrm { p } \
\hline\therefore \sim \mathrm { q }
\end{array}$

A) Law of Syllogism
B) Law of Contraposition
C) Fallacy of the Converse
D) Fallacy of the Inverse

Quizplus · Accepted Answer

The argument commits the fallacy of the inverse, which incorrectly assumes that if $p$ implies $q$, then not-$p$ implies not-$q$.

Identify the Standard Form of the Argument p→q∼p∴∼q\begin{array} { l } \mathrm { p } \rightarrow \mathrm { q } \\\sim \mathrm { p } \\\hline\therefore \sim \mathrm { q }\end{array}p→q∼p∴∼q​​

Identify the Standard Form of the Argument $\begin{array} { l } \mathrm { p } \rightarrow \mathrm { q } \\\sim \mathrm { p } \\\hline\therefore \sim \mathrm { q }\end{array}$