Two marbles are drawn without replacement from a box with 3 white, 2 green, 2 red, and 1 blue marble. Find the probability.
-The second marble is red given the first marble is white.
A) $\frac { 3 } { 32 }$
B) $\frac { 3 } { 28 }$
C) $\frac { 2 } { 7 }$
D) $\frac { 1 } { 4 }$

Question

Two marbles are drawn without replacement from a box with 3 white, 2 green, 2 red, and 1 blue marble. Find the probability.
-The second marble is red given the first marble is white. 
A) $\frac { 3 } { 32 }$
B) $\frac { 3 } { 28 }$
C) $\frac { 2 } { 7 }$
D) $\frac { 1 } { 4 }$

Quizplus · Accepted Answer

Given the first marble drawn is white, there are now 7 marbles left (2 white, 2 green, 2 red, and 1 blue). The probability that the second marble is red is the number of red marbles left (2) divided by the total number of marbles left (7), which is $\frac{2}{7}$.

Two Marbles Are Drawn Without Replacement from a Box with 3