Two marbles are drawn without replacement from a box with 3 white, 2 green, 2 red, and 1 blue marble. Find the probability.
-The second marble is white given the first marble is blue.
A) $\frac { 3 } { 8 }$
B) $\frac { 3 } { 7 }$
C) $\frac { 3 } { 64 }$
D) $\frac { 3 } { 56 }$

Question

Two marbles are drawn without replacement from a box with 3 white, 2 green, 2 red, and 1 blue marble. Find the probability.
-The second marble is white given the first marble is blue. 
A) $\frac { 3 } { 8 }$
B) $\frac { 3 } { 7 }$
C) $\frac { 3 } { 64 }$
D) $\frac { 3 } { 56 }$

Quizplus · Accepted Answer

Given the first marble drawn is blue, there are now 7 marbles left in the box (3 white, 2 green, 2 red, and 0 blue). The probability that the second marble drawn is white is therefore the number of white marbles left (3) divided by the total number of marbles left (7), which is $\frac{3}{7}$.

Two Marbles Are Drawn Without Replacement from a Box with 3