Two marbles are drawn without replacement from a box with 3 white, 2 green, 2 red, and 1 blue marble. Find the probability.
-Both marbles are white.
A) $\frac { 3 } { 8 }$
B) $\frac { 3 } { 32 }$
C) $\frac { 9 } { 56 }$
D) $\frac { 3 } { 28 }$

Question

Two marbles are drawn without replacement from a box with 3 white, 2 green, 2 red, and 1 blue marble. Find the probability.
-Both marbles are white. 
A) $\frac { 3 } { 8 }$
B) $\frac { 3 } { 32 }$
C) $\frac { 9 } { 56 }$
D) $\frac { 3 } { 28 }$

Quizplus · Accepted Answer

The probability of drawing the first white marble is 3/8. After drawing one white marble, there are 2 white marbles left out of 7 total marbles, so the probability of drawing a second white marble is 2/7. Multiply these probabilities: (3/8) * (2/7) = 6/56 = 3/28.

Two Marbles Are Drawn Without Replacement from a Box with 3