Two marbles are drawn without replacement from a box with 3 white, 2 green, 2 red, and 1 blue marble. Find the probability.
-One marble is white and one marble is blue.
A) $\frac { 1 } { 2 }$
B) $\frac { 3 } { 56 }$
C) $\frac { 3 } { 28 }$
D) $\frac { 1 } { 4 }$

Question

Two marbles are drawn without replacement from a box with 3 white, 2 green, 2 red, and 1 blue marble. Find the probability.
-One marble is white and one marble is blue. 
A) $\frac { 1 } { 2 }$
B) $\frac { 3 } { 56 }$
C) $\frac { 3 } { 28 }$
D) $\frac { 1 } { 4 }$

Quizplus · Accepted Answer

The probability of drawing one white and one blue marble can be calculated by considering the total number of ways to draw one white and one blue marble divided by the total number of ways to draw any two marbles from the box. The total number of marbles is 3 white + 2 green + 2 red + 1 blue = 8 marbles. The number of ways to choose one white marble is 3 (since there are 3 white marbles), and the number of ways to choose one blue marble is 1 (since there is only 1 blue marble). Thus, the number of ways to choose one white and one blue marble is 3 * 1 = 3. The total number of ways to choose any two marbles from 8 is 8 choose 2 = 8! / (2!(8-2)!) = 28. Therefore, the probability is 3 / 28.

Two Marbles Are Drawn Without Replacement from a Box with 3