Factor completely. -x³y + 6x²y² + 8xy³ A) xy(x + 4y)(x + 2y) B) y(x + 4y)(xy + 2y²) C) x(xy + 4y²)(x + 2y) D) xy(x² + 6x + 8y²)

Name: Factor completely. -x 3 y + 6x 2 y 2 + 8xy 3 A) xy(x + 4y)(x + 2y) B) y(x + 4y)(xy + 2y 2 ) C) x(xy + 4y 2 )(x + 2y) D) xy(x 2 + 6x + 8y 2 )
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Question

Quizplus · Accepted Answer

The given expression can be factored by first taking out the common factor, which is xy, leaving us with a quadratic expression in terms of x and y that can be factored into (x + 4y)(x + 2y).

Factor Completely. -X3y + 6x2y2 + 8xy3

Factor Completely. -X³y + 6x²y² + 8xy³