Factor completely using the trial and error method to factor trinomials. If unfactorable, indicate that the polynomial is
prime.
-$$3 x ^ { 2 } + 34 x + 11$$
A) $( 3 x + 1 ) ( x + 11 )$
B) prime
C) $( 3 x - 1 ) ( x - 11 )$
D) $( 3 x + 11 ) ( x + 1 )$

Question

Quizplus · Accepted Answer

The correct factorization of $3x^2 + 34x + 11$ is $(3x + 1)(x + 11)$. This is because when you multiply the two binomials, you get $3x^2 + 33x + x + 11$, which simplifies to $3x^2 + 34x + 11$, matching the original expression.

Factor Completely Using the Trial and Error Method to Factor 3x2+34x+113 x ^ { 2 } + 34 x + 113x2+34x+11

Factor Completely Using the Trial and Error Method to Factor $3 x ^ { 2 } + 34 x + 11$