Solve the problem.
-$$\left\{ \begin{array} { l }
\frac { 1 } { 2 } x + \frac { 1 } { 2 } y = - 1 \
x - y = 4
\end{array} \right.$$
A) $\{ ( 0 , - 2 ) \}$
B) no solution; $\varnothing$
C) $\{ ( 1 , - 3 ) \}$
D) $\{ ( - 1 , - 2 ) \}$

Question

Solve the problem.
-$$\left\{ \begin{array} { l } 
\frac { 1 } { 2 } x + \frac { 1 } { 2 } y = - 1 \
x - y = 4
\end{array} \right.$$
A) $\{ ( 0 , - 2 ) \}$
B) no solution; $\varnothing$
C) $\{ ( 1 , - 3 ) \}$
D) $\{ ( - 1 , - 2 ) \}$

Quizplus · Accepted Answer

Solving the system of equations, we find that $x = 1$ and $y = -3$, which corresponds to the solution $(1, -3)$.

Solve the Problem {12x+12y=−1x−y=4\left\{ \begin{array} { l } \frac { 1 } { 2 } x + \frac { 1 } { 2 } y = - 1 \\x - y = 4\end{array} \right.{21​x+21​y=−1x−y=4​

Solve the Problem $\left\{ \begin{array} { l } \frac { 1 } { 2 } x + \frac { 1 } { 2 } y = - 1 \\x - y = 4\end{array} \right.$