Solve the problem.
-$$\left\{ \begin{array} { l }
y - 6 x = 4 \
4 y = 24 x + 16 \
\text { A) } \{ ( - 1.5 , - 1 )
\end{array} \right.$$
A) $\{ ( - 1.5 , - 1 ) \}$
B) no solution; $\varnothing$
C) $\{ ( 1,1 ) \}$
D) infinitely many solutions; $\{ ( x , y ) \mid y - 6 x = 4 \}$ or $\{ ( x , y ) \mid 4 y = 24 x + 16 \}$

Question

Solve the problem.
-$$\left\{ \begin{array} { l } 
y - 6 x = 4 \
4 y = 24 x + 16 \
\text { A) } \{ ( - 1.5 , - 1 )
\end{array} \right.$$
A) $\{ ( - 1.5 , - 1 ) \}$
B) no solution; $\varnothing$
C) $\{ ( 1,1 ) \}$
D) infinitely many solutions; $\{ ( x , y ) \mid y - 6 x = 4 \}$ or $\{ ( x , y ) \mid 4 y = 24 x + 16 \}$

Quizplus · Accepted Answer

The two equations are equivalent, representing the same line, hence there are infinitely many solutions.

Solve the Problem {y−6x=44y=24x+16 A) {(−1.5,−1)\left\{ \begin{array} { l } y - 6 x = 4 \\4 y = 24 x + 16 \\\text { A) } \{ ( - 1.5 , - 1 )\end{array} \right.⎩⎨⎧​y−6x=44y=24x+16 A) {(−1.5,−1)​

Solve the Problem $\left\{ \begin{array} { l } y - 6 x = 4 \\4 y = 24 x + 16 \\\text { A) } \{ ( - 1.5 , - 1 )\end{array} \right.$