Solve using Cramer's rule, if possible. If it is not possible, state whether the system is inconsistent or has infinitely many
solutions.
-$$\left\{ \begin{array} { l }
4 x - 2 y = 26 \
4 x + 5 y = 33
\end{array} \right.$$
A) $( 7,1 )$
B) $( 1,7 )$
C) $( - 7 , - 1 )$
D) $( - 1,7 )$

Question

Solve using Cramer's rule, if possible. If it is not possible, state whether the system is inconsistent or has infinitely many
solutions.
-$$\left\{ \begin{array} { l } 
4 x - 2 y = 26 \
4 x + 5 y = 33
\end{array} \right.$$
A) $( 7,1 )$
B) $( 1,7 )$
C) $( - 7 , - 1 )$
D) $( - 1,7 )$

Quizplus · Accepted Answer

Cramer's rule involves calculating determinants. The determinant of the coefficient matrix is $|A| = 4(5) - (-2)(4) = 20 + 8 = 28$, which is non-zero, so the system has a unique solution. Solving for $x$ and $y$ using Cramer's rule gives $x = 7$ and $y = 1$, so the solution is $(7, 1)$.

Solve Using Cramer's Rule, If Possible {4x−2y=264x+5y=33\left\{ \begin{array} { l } 4 x - 2 y = 26 \\4 x + 5 y = 33\end{array} \right.{4x−2y=264x+5y=33​

Solve Using Cramer's Rule, If Possible $\left\{ \begin{array} { l } 4 x - 2 y = 26 \\4 x + 5 y = 33\end{array} \right.$