Solve using Cramer's rule, if possible. If it is not possible, state whether the system is inconsistent or has infinitely many
solutions.
-$$\left\{ \begin{array} { l }
3 x + 2 y = 23 \
3 x - 3 y = 3
\end{array} \right.$$
A) $( - 4,5 )$
B) $( 4,5 )$
C) $( - 5 , - 4 )$
D) $( 5,4 )$

Question

Solve using Cramer's rule, if possible. If it is not possible, state whether the system is inconsistent or has infinitely many
solutions.
-$$\left\{ \begin{array} { l } 
3 x + 2 y = 23 \
3 x - 3 y = 3
\end{array} \right.$$
A) $( - 4,5 )$
B) $( 4,5 )$
C) $( - 5 , - 4 )$
D) $( 5,4 )$

Quizplus · Accepted Answer

The determinant of the coefficient matrix is non-zero, so Cramer's rule can be applied. Solving using Cramer's rule gives the solution $(5, 4)$.

Solve Using Cramer's Rule, If Possible {3x+2y=233x−3y=3\left\{ \begin{array} { l } 3 x + 2 y = 23 \\3 x - 3 y = 3\end{array} \right.{3x+2y=233x−3y=3​

Solve Using Cramer's Rule, If Possible $\left\{ \begin{array} { l } 3 x + 2 y = 23 \\3 x - 3 y = 3\end{array} \right.$