Solve for x.
-$$\left| \begin{array} { l l l }
4 & x & 1 \
- 4 & 1 & 0 \
5 & 1 & 3
\end{array} \right| = 39$$
A) $- 2$
B) 3
C) 24
D) 5

Question

Solve for x.
-$$\left| \begin{array} { l l l } 
4 & x & 1 \
- 4 & 1 & 0 \
5 & 1 & 3
\end{array} \right| = 39$$
A) $- 2$
B) 3
C) 24
D) 5

Quizplus · Accepted Answer

To solve for x, calculate the determinant of the matrix and set it equal to 39. The determinant is calculated as: $4(1*3 - 0*1) - x(-4*3 - 0*5) + 1(-4*1 - 1*5)$. Simplifying gives $12 + 12x - 9 = 39$. Solving for x gives $12x = 36$, so $x = 3$.

Solve for X ∣4x1−410513∣=39\left| \begin{array} { l l l } 4 & x & 1 \\- 4 & 1 & 0 \\5 & 1 & 3\end{array} \right| = 39​4−45​x11​103​​=39

Solve for X $\left| \begin{array} { l l l } 4 & x & 1 \\- 4 & 1 & 0 \\5 & 1 & 3\end{array} \right| = 39$