Use the quadratic formula to solve the equation.
-$x ( 2 x + 5 ) = 2$
A) $\frac { 5 - 3 } { 4 } , \frac { 5 + 3 } { 4 }$
B) $\frac { 5 - \sqrt { 41 } } { 4 } , \frac { 5 + \sqrt { 41 } } { 4 }$
C) $\frac { - 5 - 3 } { 4 } , \frac { - 5 + 3 } { 4 }$
D) $\frac { - 5 - \sqrt { 41 } } { 4 } , \frac { - 5 + \sqrt { 41 } } { 4 }$

Question

Quizplus · Accepted Answer

The equation can be rewritten as $2x^2 + 5x - 2 = 0$. Using the quadratic formula $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$, where $a = 2$, $b = 5$, and $c = -2$, we find the solutions are $\frac{-5 \pm \sqrt{41}}{4}$.

Use the Quadratic Formula to Solve the Equation x(2x+5)=2x ( 2 x + 5 ) = 2x(2x+5)=2

Use the Quadratic Formula to Solve the Equation $x ( 2 x + 5 ) = 2$