Solve
-The Base of a Triangle Is 4 More Than $2 + \sqrt { 83 } \mathrm {~cm}$

Solve.
-The base of a triangle is 4 more than twice its height. If the area of the triangle is 82 square centimeters, find its base and height.

A) height: $2 + \sqrt { 83 } \mathrm {~cm}$
base: $- 1 + \sqrt { 83 } \mathrm {~cm}$

B) height: $- 1 + \sqrt { 83 } \mathrm {~cm}$
base: $2 + 2 \sqrt { 83 } \mathrm {~cm}$

C) height: $- 1 + \sqrt { 83 } \mathrm {~cm}$
base: $2 + \sqrt { 83 } \mathrm {~cm}$

D) height: $2 + 2 \sqrt { 83 } \mathrm {~cm}$
base: $- 1 + \sqrt { 83 } \mathrm {~cm}$