Solve.
-The length and width of a rectangle must have a sum of 68 feet. Find the dimensions of the rectangle whose area is as large as possible.
A) length $34 \mathrm { ft }$; width $34 \mathrm { ft }$
B) length $34 \mathrm { ft }$; width $102 \mathrm { ft }$
C) length $33 \mathrm { ft }$; width $35 \mathrm { ft }$
D) length $\frac { 1 } { 34 } \mathrm { ft }$; width $\frac { 13 } { 34 } \mathrm { ft }$

Question

Quizplus · Accepted Answer

The maximum area of a rectangle, given a fixed perimeter, is achieved when the rectangle is a square. Since the sum of the length and width is 68 feet, dividing this equally gives dimensions of 34 ft by 34 ft.

Solve -The Length and Width of a Rectangle Must Have 34ft34 \mathrm { ft }34ft

Solve
-The Length and Width of a Rectangle Must Have $34 \mathrm { ft }$