Solve.
-An arrow is fired into the air with an initial velocity of 96 feet per second. The height in feet of the arrow $t$ seconds after it was shot into the air is given by the function $h ( t ) = - 16 t ^ { 2 } + 96 t$. Find the maximum height of the arrow.
A) $432 \mathrm { ft }$
B) $144 \mathrm { ft }$
C) $48 \mathrm { ft }$
D) $240 \mathrm { ft }$

Question

Quizplus · Accepted Answer

The maximum height of the arrow is found at the vertex of the parabola described by the function $h(t) = -16t^2 + 96t$. The vertex occurs at $t = -\frac{b}{2a}$, where $a = -16$ and $b = 96$. Calculating this gives $t = 3$. Substituting $t = 3$ back into the function gives $h(3) = -16(3)^2 + 96(3) = 144$ feet.

Solve -An Arrow Is Fired into the Air with an Initial

Solve
-An Arrow Is Fired into the Air with an Initial