Solve the inequality. Write the solution set in interval notation.
-$x ^ { 2 } - 6 x \geq - 8$
A) $( - \infty , 2 ] \cup [ 4 , \infty )$
B) $( - \infty , 2 ]$
C) $[ 4 , \infty )$
D) $[ 2,4 ]$

Question

Quizplus · Accepted Answer

The inequality can be rewritten as $x^2 - 6x + 8 \geq 0$. Factoring gives $(x-2)(x-4) \geq 0$. The solution set is where the product is non-negative, which occurs in the intervals $(-\infty, 2] \cup [4, \infty)$.

Solve the Inequality x2−6x≥−8x ^ { 2 } - 6 x \geq - 8x2−6x≥−8

Solve the Inequality $x ^ { 2 } - 6 x \geq - 8$