Solve the inequality. Write the solution set in interval notation.
-$\frac { 4 x - 24 } { x ^ { 2 } - 1 } \geq 0$
A) $( - 1,6 ]$
B) $( - 1,1 ) \cup [ 6 , \infty )$
C) $[ - 1,1 ] \cup [ 6 , \infty )$
D) $( \infty , 1 ) \cup [ 6 , \infty )$

Question

Quizplus · Accepted Answer

The inequality is equivalent to $( x - 6 ) ( x + 4 ) \geq 0$. The solution set is the union of the intervals $( - \infty , - 4 ]$ and $[ 6 , \infty )$.

Solve the Inequality 4x−24x2−1≥0\frac { 4 x - 24 } { x ^ { 2 } - 1 } \geq 0x2−14x−24​≥0

Solve the Inequality $\frac { 4 x - 24 } { x ^ { 2 } - 1 } \geq 0$