Solve. Give exact solutions.
-$$3 z ^ { 2 } + 432 = 0$$
A) $\pm 12 \mathrm { i }$
B) $\pm 12$
C) 12
D) $12 \mathrm { i }$

Question

Quizplus · Accepted Answer

To solve the equation $3z^2 + 432 = 0$, subtract 432 from both sides to get $3z^2 = -432$. Then, divide by 3 to isolate $z^2$, resulting in $z^2 = -144$. Taking the square root of both sides gives $z = \pm \sqrt{-144}$, which simplifies to $z = \pm 12i$, since the square root of -1 is $i$.

Solve Give Exact Solutions 3z2+432=03 z ^ { 2 } + 432 = 03z2+432=0

Solve Give Exact Solutions $3 z ^ { 2 } + 432 = 0$