Solve. Give exact solutions.
-$$4 x ^ { 2 } + 36 = 0$$
A) $\pm 3 i$
B) $3 \pm i$
C) $\pm 3$
D) $\pm 3 + \mathrm { i }$

Name: Solve. Give exact solutions. -\[4 x ^ { 2 } + 36 = 0\] A) $\pm 3 i$ B) $3 \pm i$ C) $\pm 3$ D) $\pm 3 + \mathrm { i }$
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Question

Quizplus · Accepted Answer

To solve the equation $4x^2 + 36 = 0$, subtract 36 from both sides to get $4x^2 = -36$. Then divide by 4 to get $x^2 = -9$. Taking the square root of both sides gives $x = \pm \sqrt{-9}$, which simplifies to $x = \pm 3i$.

Solve Give Exact Solutions 4x2+36=04 x ^ { 2 } + 36 = 04x2+36=0

Solve Give Exact Solutions $4 x ^ { 2 } + 36 = 0$