Find the x-intercepts.
-$$f ( x ) = 11 x ^ { 2 } - 3 x - 6$$
A) No x-intercepts
B) $( 9,0 )$ and $( 6,0 )$
C) $\left( \frac { 3 + \sqrt { 273 } } { 22 } , 0 \right)$ and $\left( \frac { 3 - \sqrt { 273 } } { 22 } , 0 \right)$
D) $\left( \frac { 3 + \sqrt { 261 } } { 22 } , 0 \right)$ and $\left( \frac { 3 - \sqrt { 261 } } { 22 } , 0 \right)$

Question

Quizplus · Accepted Answer

To find the x-intercepts of the quadratic equation $f(x) = 11x^2 - 3x - 6$, we set $f(x) = 0$ and solve for $x$ using the quadratic formula $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$, where $a = 11$, $b = -3$, and $c = -6$. Plugging these values into the formula gives $x = \frac{3 \pm \sqrt{(-3)^2 - 4(11)(-6)}}{2(11)}$, which simplifies to $x = \frac{3 \pm \sqrt{9 + 264}}{22}$ or $x = \frac{3 \pm \sqrt{273}}{22}$.

Find the X-Intercepts f(x)=11x2−3x−6f ( x ) = 11 x ^ { 2 } - 3 x - 6f(x)=11x2−3x−6

Find the X-Intercepts $f ( x ) = 11 x ^ { 2 } - 3 x - 6$