Solve. Round results to the nearest thousandth.
-$3 y ^ { 2 } - 4 y = 1$
A) $1.000,0.333$
B) $0.215 , - 1.549$
C) $1.549 , - 0.215$
D) $3.098 , - 0.430$

Question

Quizplus · Accepted Answer

First, rearrange the equation to standard form: $3y^2 - 4y - 1 = 0$. Then, use the quadratic formula $y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$ with $a = 3$, $b = -4$, and $c = -1$. This gives $y = \frac{4 \pm \sqrt{(-4)^2 - 4(3)(-1)}}{2(3)} = \frac{4 \pm \sqrt{16 + 12}}{6} = \frac{4 \pm \sqrt{28}}{6}$, which simplifies to $y = 1.549$ and $y = -0.215$, rounded to the nearest thousandth.

Solve Round Results to the Nearest Thousandth 3y2−4y=13 y ^ { 2 } - 4 y = 13y2−4y=1

Solve Round Results to the Nearest Thousandth $3 y ^ { 2 } - 4 y = 1$