Solve.
-$49 \mathrm { t } ^ { 3 } + 16 \mathrm { t } = - 70 \mathrm { t } ^ { 2 }$
A) $- \frac { 8 } { 49 } , \frac { 24 } { 49 }$
B) $0 , - \frac { 2 } { 7 } , - \frac { 8 } { 7 }$
C) $- \frac { 2 } { 7 } , - \frac { 8 } { 7 }$
D) $0 , \frac { 2 } { 7 } , \frac { 8 } { 7 }$

Question

Quizplus · Accepted Answer

First, rearrange the equation to set it to 0: $49t^3 + 16t + 70t^2 = 0$. Factoring out $t$, we get $t(49t^2 + 70t + 16) = 0$. Factoring the quadratic part gives $t(7t + 8)(7t + 2) = 0$, leading to the solutions $t = 0$, $t = -\frac{8}{7}$, and $t = -\frac{2}{7}$.

Solve - 49t3+16t=−70t249 \mathrm { t } ^ { 3 } + 16 \mathrm { t } = - 70 \mathrm { t } ^ { 2 }49t3+16t=−70t2

Solve
- $49 \mathrm { t } ^ { 3 } + 16 \mathrm { t } = - 70 \mathrm { t } ^ { 2 }$