Solve.
-$$x ^ { 2 } + 12 x + 36 = 17$$
A) $6 + \sqrt { 17 } , 6 - \sqrt { 17 }$
B) 11
C) $- 6 + \sqrt { 17 } , - 6 - \sqrt { 17 }$
D) $\sqrt { 17 } , - \sqrt { 17 }$

Question

Quizplus · Accepted Answer

The equation can be rewritten as $(x + 6)^2 = 17$ by recognizing the left side as a perfect square trinomial. Solving for $x$ gives $x = -6 \pm \sqrt{17}$, which matches choice C.

Solve - x2+12x+36=17x ^ { 2 } + 12 x + 36 = 17x2+12x+36=17

Solve
- $x ^ { 2 } + 12 x + 36 = 17$