$\text { For the curve } r ( t ) \text {, write the acceleration in the form aTT } + \text { anN. }$
-r(t) = (6t sin t + 6 cos t)i + (6t cos t - 6 sin t)j + 3k
A) $a = 6 T + 6 t N$
B) $a = \frac { 1 } { 6 t } N$
C) $a = 6 T + \frac { 1 } { 6 t } N$
D) $a = 6 \mathrm { t }$

Question

$\text { For the curve } r ( t ) \text {, write the acceleration in the form aTT } + \text { anN. }$
-r(t) = (6t sin t + 6 cos t)i + (6t cos t - 6 sin t)j + 3k 
A) $a = 6 T + 6 t N$
B) $a = \frac { 1 } { 6 t } N$
C) $a = 6 T + \frac { 1 } { 6 t } N$
D) $a = 6 \mathrm { t }$

Quizplus · Accepted Answer

The acceleration vector can be expressed in terms of the tangential and normal components, where $a_T$ is the tangential acceleration and $a_N$ is the normal acceleration. For the given curve, the tangential component is 6, and the normal component is $6t$.

For the curve r(t), write the acceleration in the form aTT + anN. \text { For the curve } r ( t ) \text {, write the acceleration in the form aTT } + \text { anN. } For the curve r(t), write the acceleration in the form aTT + anN.

$\text { For the curve } r ( t ) \text {, write the acceleration in the form aTT } + \text { anN. }$