Solve the Problem $\frac { x ^ { 2 } } { 7 } + \frac { y ^ { 2 } } { 3 } = 1$

Solve the problem.
-The ellipse $\frac { x ^ { 2 } } { 7 } + \frac { y ^ { 2 } } { 3 } = 1$ is shifted up 5 units and left 5 units. Find an equation for the new ellipse and find the new vertices.

A) $\frac { ( x + 5 ) ^ { 2 } } { 7 } + \frac { ( y - 5 ) ^ { 2 } } { 3 } = 1$ ; vertices: $( - 5 \pm \sqrt { 7 } , 5 )$
B) $\frac { ( x + 5 ) ^ { 2 } } { 7 } + \frac { ( y - 5 ) ^ { 2 } } { 3 } = 1$ ; vertices: $( - 5,5 \pm \sqrt { 3 } )$
C) $\frac { ( x - 5 ) ^ { 2 } } { 7 } + \frac { ( y + 5 ) ^ { 2 } } { 3 } = 1$ ; vertices: $( - 5 \pm \sqrt { 7 } , 5 )$ .
D) $\frac { ( x + 5 ) ^ { 2 } } { 7 } + \frac { ( y - 5 ) ^ { 2 } } { 3 } = 1$ ; vertices: $( - 5,5 \pm \sqrt { 3 } )$ .