Find the interval of convergence of the series.
-$$\sum _ { \mathrm { n } = 0 } ^ { \infty } \frac { ( \mathrm { x } - 3 ) ^ { \mathrm { n } } } { 9 + 7 \mathrm { n } }$$
A) $- 4

Question

Find the interval of convergence of the series.
-$$\sum _ { \mathrm { n } = 0 } ^ { \infty } \frac { ( \mathrm { x } - 3 ) ^ { \mathrm { n } } } { 9 + 7 \mathrm { n } }$$
A) $- 4 < x < 10$
B) $\frac { 11 } { 9 } < x < \frac { 43 } { 9 }$
C) $- 4 \leq x \leq 10$
D) $2 \leq x < 4$

Quizplus · Accepted Answer

The Answer of Find the interval of convergence of the series.
-$$\sum _ { \mathrm { n } = 0 } ^ { \infty } \frac { ( \mathrm { x } - 3 ) ^ { \mathrm { n } } } { 9 + 7 \mathrm { n } }$$
A) $- 4 < x < 10$
B) $\frac { 11 } { 9 } < x < \frac { 43 } { 9 }$
C) $- 4 \leq x \leq 10$
D) $2 \leq x < 4$

Find the Interval of Convergence of the Series ∑n=0∞(x−3)n9+7n\sum _ { \mathrm { n } = 0 } ^ { \infty } \frac { ( \mathrm { x } - 3 ) ^ { \mathrm { n } } } { 9 + 7 \mathrm { n } }n=0∑∞​9+7n(x−3)n​

Find the Interval of Convergence of the Series $\sum _ { \mathrm { n } = 0 } ^ { \infty } \frac { ( \mathrm { x } - 3 ) ^ { \mathrm { n } } } { 9 + 7 \mathrm { n } }$